4x^2+10x-6=2(2x-1)(x+3)

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Solution for 4x^2+10x-6=2(2x-1)(x+3) equation: 



4x^2+10x-6=2(2x-1)(x+3)

We move all terms to the left:

4x^2+10x-6-(2(2x-1)(x+3))=0

We multiply parentheses ..

4x^2-(2(+2x^2+6x-1x-3))+10x-6=0



We calculate terms in parentheses: -(2(+2x^2+6x-1x-3)), so:

2(+2x^2+6x-1x-3)

We multiply parentheses

4x^2+12x-2x-6

We add all the numbers together, and all the variables

4x^2+10x-6

Back to the equation:

-(4x^2+10x-6)



We add all the numbers together, and all the variables

4x^2+10x-(4x^2+10x-6)-6=0

We get rid of parentheses

4x^2-4x^2+10x-10x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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